Jeez, got to slow down. Should be LT. myDG.verticalScrollPosition = (myDataProvider.length - array[i]) < (myDataProvider.length - myDG.rowCount) ? (myDataProvider.length - myDG.rowCount) : array[i];
-TH --- In [email protected], "Tim Hoff" <[EMAIL PROTECTED]> wrote: > > > Sorry for the typo, also not tested; obviously. :) > > myDG.verticalScrollPosition = (myDataProvider.length - array[i]) > > (myDataProvider.length - myDG.rowCount) ? (myDataProvider.length - > myDG.rowCount) : array[i]; > > -TH > > --- In [email protected], "Tim Hoff" TimHoff@ wrote: > > > > > > Hi Mark, > > > > You can come probably up with a more elegant way to handle each > > possibility, but here's an idea. > > > > myDG.verticalScrollPosition = (myDataProvider - array[i]) > > > (myDataProvider.length - myDG.rowCount) ? (myDataProvider.length - > > myDG.rowCount) : array[i]; > > > > -TH > > > > --- In [email protected], "Mark" markp.shopping_id@ wrote: > > > > > > I have a basic datagrid that is getting the data from an > > > arrayCollection with each item having a startDate field, among > > > others. My boss wanted me to have the datagrid scroll down to the > > > item that has the same start date as todays date. Basically I'm just > > > looping thru the arrayCollection to find it and scroll down to it > > > using: > > > > > > myDG.verticalScrollPosition = array[i]; > > > > > > This works fine unless that item is at the end of the datagrid. Then > > > it adds rows to the DG so that item is at top. What would be the > > > proper way to do this so if it's the last item, it just scrolls to > the > > > bottom without adding more rows? > > > > > > Thanks, > > > Mark > > > > > >
