That is exactly what I was looking for. Thank you very much, Ken.
Matt
--- In [email protected], "Kenneth Sutherland"
<kenneth.sutherl...@...> wrote:
>
> Not sure I'm getting 100% what you're doing but hopefully this will help
> you.
>
> For page X you would do:
>
> Min index = ( X - 1 ) * number of records per page
>
> Max index = Min + (number of records per page - 1)
>
> So page 1 gives you:
>
> Min index is ->(1 - 1) * 4 = 0;
>
> Max index is -> 0 + (4 - 1 ) = 3;
>
>
>
> Page 4 gives you:
>
> Min index is ->(4 - 1) * 4 = 12;
>
> Max index is -> 12 + (4 - 1 ) = 15;
>
>
>
> To get a page number from an index do this:
>
> Math.floor(Index / number of index per page) + 1;
>
> So index 3 gives you Math.floor(3 / 4) + 1 = 1;
>
>
>
> So index 14 gives you Math.floor(14 / 4) + 1 = 4;
>
>
>
> (your example below had 5 records per page not 4 as you had typed)
>
>
>
> HTH Kenneth.
>
>
>
>
>
> From: [email protected] [mailto:[email protected]] On
> Behalf Of fumeng5
> Sent: 29 May 2009 15:59
> To: [email protected]
> Subject: [flexcoders] Need help writing alorithm
>
>
>
>
>
>
>
>
> Hi,
>
> I'm looking for help writing an algorithm in a filter function I am
> using. Here's the situation: Based on a page number and a number of
> records per page, I want to return all indexes that fall within a
> certain range. There are 4 records per page.
>
> For example;
>
> - page 1 will return indexes 0-4
> - page 2 will return indexes 5 - 9
> - page 3 will return indexes 10 - 14
> ....etc, etc...
>
> So, here are the vars:
>
> var index:int = myCollection.getItemIndex( item );
> var recordsPerPage:int = 4;
>
> It's embarrassing, but this is what I have so far....
>
> if( page <= index < (page * page + recordsPerPage) )
> return true
>
> Can anyone offer some helpful insight, please?
>
> Thank you for any help.
>
>
>
>
>
>
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