If you can see the xml when you do: var myXML:XML = XML(event.result);
trace(myXML.toXMLString()); //do yo see the whole xml? then go one level deeper: myXML = myXML.data[0] trace(myXML.toXMLString()); //do you see the data xml If so, go one level deeper, and trace that, etc. Tracy Spratt, Lariat Services, development services available _____ From: [email protected] [mailto:[email protected]] On Behalf Of valdhor Sent: Friday, March 19, 2010 8:31 AM To: [email protected] Subject: [flexcoders] Re: Problem reading an XML file I am not very good with XML (That's Tracy's expertise) but you can get it with the following: myXML..woeid myXML[0]..woeid and probably a dozen different ways. You may like to check these out for more detail... http://www.adobe. <http://www.adobe.com/devnet/flex/quickstart/accessing_xml_data/> com/devnet/flex/quickstart/accessing_xml_data/ http://livedocs. <http://livedocs.adobe.com/flex/3/langref/XML.html> adobe.com/flex/3/langref/XML.html --- In flexcod...@yahoogro <mailto:flexcoders%40yahoogroups.com> ups.com, "Sneha" <bhansal...@...> wrote: > > Hello All, > > Can anybody help me find out the bug in my program which doesn't read children in an XML file. > > I am trying to get WOEID of the location provided from Yahoo webservice API. I have given below what I am doing and also the XML file generated from Yahoo. > > <mx:HTTPService > id="weatherService" > url = " > http://where. <http://where.yahooapis.com/v1/places.q> yahooapis.com/v1/places.q('{txtCity.text}');start=0;count=1?appid=your AppID" > result="getWOEID(event)" fault="faultEventHandler(event)" > resultFormat=" > e4x"/> > > This is what I am doing in Script tag. But nothing works. I am able to read the complete XML file but not the children of an XML file. Could someone help find the problem. > private > function init():void{ > var city:String = txtCity.text; > //Alert.show("Your City:"+city); > weatherService.cancel(); > //var params:Object = new Object(); > //params.q = city; > //Alert.show("params.q"+params.q); > //weatherService.send(params); > weatherService.send(); > } > private function getWOEID(event:ResultEvent):void{ > var myXML:XML = XML(event.result); > taXML.text = myXML; > var cityList:XMLList = myXML.data.place.children(); > Alert.show( > "getting woeid:" +cityList); > //taXML = cityList.toString(); > //cityList = myXML.places.place.name ; > //cityList = myXML.place.woeid; > //Alert.show("in getWOEID() " +cityList); > //lblWOEID.text = cityList; > } > This is the XML file generated and I am interested in accessing <woeid>: > > <places yahoo:start="0" yahoo:count="1" yahoo:total="55"> > − > <place yahoo:uri="http://where. <http://where.yahooapis.com/v1/place/2371464> yahooapis.com/v1/place/2371464" xml:lang="en-us"> > <woeid>2371464</woeid> > <placeTypeName code="7">Town</placeTypeName> > <name>Buffalo</name> > <country type="Country" code="US">United States</country> > <admin1 type="State" code="US-NY">New York</admin1> > <admin2 type="County" code="">Erie</admin2> > <admin3/> > <locality1 type="Town">Buffalo</locality1> > <locality2/> > <postal/> > − > <centroid> > <latitude>42.885441</latitude> > <longitude>-78.878464</longitude> > </centroid> > − > <boundingBox> > − > <southWest> > <latitude>42.824860</latitude> > <longitude>-78.942909</longitude> > </southWest> > − > <northEast> > <latitude>42.970741</latitude> > <longitude>-78.771393</longitude> > </northEast> > </boundingBox> > </place> > </places> > > Any help would be appreciated. > > Thank you > > Sneha >
