Thanks for this tip.
But, I came across another thing. How would I set the width of the column so that it matches the width of the itemrenderers inside it? Apparently, setting the width to 100% for the datagrid column is not allowed. Thanks. Angelo ________________________________ From: Christopher McArthur <[email protected]> To: [email protected] Sent: Thu, 20 May, 2010 17:14:06 Subject: RE: [flexcoders] Set Width of An Item Renderer Component Based on Visible Property of the Control the "includeInLayout" property may also be helpful to you in this case, try: includeInLayout="{outerDocument. fncVisible( )}" From:flexcod...@yahoogro ups.com [mailto:flexcoders@ yahoogroups. com] On Behalf Of Angelo Anolin Sent: Thursday, May 20, 2010 2:46 PM To: flexcod...@yahoogro ups.com Subject: [flexcoders] Set Width of An Item Renderer Component Based on Visible Property of the Control Hi FlexCoders, I have declared an in-line item renderer in my datagrid: <mx:DataGridColumn headerText="Test" textAlign="center" sortable="false"> <mx:itemRenderer> <mx:Component> <mx:HBox horizontalAlign="center" > <mx:LinkButton id="lnk1" label="Link 1" visible={outerDocum ent.fncVisible( )}" width="{???}"/> <mx:LinkButton id="lnk1" label="Link 1" /> <mx:LinkButton id="lnk1" label="Link 1" /> </mx:HBox> </mx:Component> </mx:itemRenderer> </mx:DataGridColumn> as you may see, I am determining the visibility of the link button via a function. What I want to achieve is that if the linkbutton contrl is invisible, the width should be 0, but if it is visible, then width should be 100. How do I pass in a function for the width of the control whether it's visibility is set to true or false? Thanks.
