Thanks. In this case the status values are the newArrayHashMap
keys. I am populating a comboBox with the results from the
function. The comboBox is then used to filter an arrayCollection
that has the same underlying array that is used in the function -
"array". "status", is a member of the value objects (accountVO)
that are contained in "array". The task was to dynamically load the
comboBox with the unique "status" values that exist in the database.
For instance the accounts database might contain the following
fields:
accountId : String;
accountName : String;
status : String;
The possible status values might be "Open", "Closed" and "On Hold".
The user is presented with a data grid view of the results from an
accounts search. At this time, the user may wish to filter the
results to
only show the "Closed" accounts. Sure, the values in the comboBox
could be hard coded. But the program would have to be maintained
when a new "status" value is added to the database. Also, the
comboBox should only show "status" values that exist in the search
results. If the search results included "Active" and "Inactive"
accounts, the comboBox should only present those same values. If it
was hard coded, the user would be able to select the "On Hold"
comboBox option, which in this case would present a blank dataGrid.
Don't want to confuse the user this way.
The "All" option is used programmatically to un-filter the
arrayCollection. "All" is the default value for the comboBox - in
this case only because it is alphabetically first in the function's
status array. Gordon, I think that your method of shifting
the "All" value after the array has been sorted is better - just in
case a new status value (like "Active") is added to the database. I
suppose that the function could be improved even further by changing
the name of the field ("status") to a function parameter, so that
the function may be re-used. If you're interested, I'll post a
version.
By now, I'm sure that I've acheived total confusion. If not, I hope
this helps someone.
Tim Hoff
--- In [email protected], "Gordon Smith" <[EMAIL PROTECTED]>
wrote:
>
> That's a nice improvement on my suggestion because it doesn't
require a
> second loop. But since you only care about the key, not the value,
that
> you put into newArrayHashMap, I wouldn't burden the memory manager
and
> the garbage collector by constructing a new Object() for each
value;
> using a scalar value like 1 or true would be more efficient. But
this
> will only matter if the status array will be large.
>
> Also, if "All" gets sorted alphabetically along with the other
status
> codes, will users know it's special?
>
> - Gordon
>
>
> -----Original Message-----
> From: [email protected]
[mailto:[EMAIL PROTECTED] On
> Behalf Of turbo_vb
> Sent: Wednesday, April 12, 2006 2:21 PM
> To: [email protected]
> Subject: [flexcoders] Re: AS3 Array Question
>
> Doug and Gordon, thanks for the advise. I decided on the
following
> solution.
>
> public function populateStatusArray(array:Array):void
> {
> var newArrayHashMap : Object = new Object();
> var status : Array = new Array;
> status.push("All");
>
> var n:int = array.length;
> for (var i:int = 0; i < n; i++)
> {
> if (newArrayHashMap[array[i].status] == undefined)
> {
> newArrayHashMap[array[i].status] = new Object();
> status.push(array[i].status);
> }
> }
> status.sort();
> ModelLocator.getInstance().statusArray = status;
> }
>
> Tim Hoff
>
>
> --- In [email protected], "Gordon Smith" <gosmith@>
> wrote:
> >
> > You can use a plain Object as a Set... see the code below.
> >
> > You first put key/value pairs into the Object, but it makes no
> > difference what the values are. You just care about the keys,
and
> the
> > Object's hash table takes care of ensuring that setting a key
more
> than
> > once is harmless.
> >
> > Then you iterate over the Object, pulling out the unique keys
into
> an
> > Array that can be sorted.
> >
> > Finally, you stick "All" at the top, after the sort.
> >
> > - Gordon
> >
> >
> > <?xml version="1.0" encoding="utf-8"?>
> > <mx:Application xmlns:mx="http://www.adobe.com/2006/mxml";
> width="600"
> > height="600">
> >
> > <mx:Script>
> > <![CDATA[
> >
> > [Bindable]
> > private var array:Array =
> [ "B", "C", "A", "B", "A", "D"
> > ];
> >
> > public function getUniqueItems(array:Array):Array
> > {
> > var uniqueItemHash:Object = {};
> > var n:int = array.length;
> > for (var i:int = 0; i < n; i++)
> > {
> > uniqueItemHash[array[i]] = true;
> > }
> >
> > var uniqueItemArray:Array = [];
> > for (var p:String in uniqueItemHash)
> > {
> > uniqueItemArray.push(p);
> > }
> >
> > uniqueItemArray.sort();
> > uniqueItemArray.unshift("All");
> > return uniqueItemArray;
> > }
> >
> > ]]>
> > </mx:Script>
> >
> > <mx:ComboBox dataProvider="{getUniqueItems(array)}"/>
> >
> > </mx:Application>
> >
> > -----Original Message-----
> > From: [email protected]
> [mailto:[EMAIL PROTECTED] On
> > Behalf Of Doug Lowder
> > Sent: Tuesday, April 11, 2006 5:00 PM
> > To: [email protected]
> > Subject: [flexcoders] Re: AS3 Array Question
> >
> > For large arrays, it will be more efficient to do this:
> >
> > 1) Make a copy of the input array, if necessary
> > 2) Sort the array by status
> > 3) Iterate through the array once, storing new status values and
> > skipping the duplicates
> >
> >
> > --- In [email protected], "turbo_vb" <TimHoff@> wrote:
> > >
> > > I'm trying to populate a dataProvider array for a comboBox
that
> > > contains unique status values from another array, that is used
> as
> > > the dataProvider for a dataGrid. The comboBox is used to
filter
> > the
> > > dataGrid. The code below works, but I seem to remember seeing
> > this
> > > done somewhere that doesn't use nested for statements. Does
> > anyone
> > > know how I can identify if the array's status value already
> exists
> > > in the new status array without iterating the new array every
> time?
> > >
> > > public function populateStatusArray(array:Array):void {
> > >
> > > var status : Array = new Array;
> > > status.push("All");
> > >
> > > var n:int = citations.length;
> > > for (var i:int = 0; i < n; i++) {
> > > var m:int = status.length;
> > > var found:Boolean = false;
> > > for (var j:int = 0; j < m; j++) {
> > > if (status[j] == array[i].status){
> > > found = true;
> > > }
> > > }
> > > if (found == false) {
> > > status.push(array[i].status);
> > > }
> > > }
> > > status.sort();
> > > ModelLocator.getInstance().statusArray =
> > status;
> > > }
> > >
> > > Thank You,
> > > Tim Hoff
> > >
> >
> >
> >
> >
> >
> >
> > --
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> >
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>
>
>
>
>
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