RE: [flexcoders] How can I sort a hash in Actionscript?

Mon, 08 May 2006 16:28:22 -0700

ActionScript 3.0 does have a hash class, named Dictionary, which you can
find in the flash.utils package. You can rewrite your "o" Object as a
Dictionary, but ActionScript 3.0 doesn't have the equivalent of the
'sort' keyword in Perl where you can do something like:

// Perl code
foreach $key (sort keys %hash) {}

Unless I'm mistaken, you'd have to write code to sort the Dictionary, so
you may not find this a satisfactory solution.

On the other hand, you can use the Array.sortOn() method to sort the
objects. You just have to create a separate indexed array to do it, the
following builds on your example code:

// create an indexed array that holds the objects in sorted order
var oSorted:Array = new Array();

// add your items to the indexed array
for each (var item in o) {
      oSorted.push(item);
}

// sort the indexed array based on the "order" property
oSorted.sortOn("order", Array.NUMERIC);

// Now you can iterate through the sorted array
for (var i=0; i<oSorted.length; i++) {
      trace(oSorted[i].order);
}

HTH,

Francis


> -----Original Message-----
> From: [email protected] [mailto:[EMAIL PROTECTED]
On
> Behalf Of rigidcode
> Sent: Monday, May 08, 2006 11:32 AM
> To: [email protected]
> Subject: [flexcoders] How can I sort a hash in Actionscript?
>
>
> If I have an Object (there's no hash class in Actionscript 3 right??),
> is there a way to sort it according to one of it's member's
> properties? For example:
>
> var o:Object = new Object();
>
> o['something'] = new Thing();
> Thing(o['something']).order= 20;
>
> o['another'] = new Thing();
> Thing(o['another']).order= 10;
>
> o['somethingelse'] = new Thing();
> Thing(o['somethingelse']).order= 30;
>
>
> I want to loop through o, in the order of it's member's "order"
> property.  I can do this in java and perl and php, but actionscript
> (unbelivably) has no Hash object, right? And "Object" doesn't
> implement ICollectionView.  Is there anything else I can do here using
> the API?
>
> thanks
>
>
>
>
>
>



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