many nodes there will be at any given time.
Below sounds very similar to the way I originally tried it, I will have
to give it a try again and try a few different variations.
I am wondering if there is a way to just use two trees, and have them
mirror each other. Just make one completely hidden, never render it.
Initially you set the dataprovider of both trees to the same source.
Then as nodes are opened and closed, you mimic it in the hidden tree.
After you refresh the dp of the rendered tree, you walk the displayed
nodes of the hidden tree and mimic it back. Anyone tried that approach?
I think it would be pretty straightforward and inexpensive - but that
depends on the amount of nodes. Thoughts?
Thanks for your help everyone.
Karl
-----Original Message-----
From: [email protected] [mailto:[EMAIL PROTECTED] On
Behalf Of Tracy Spratt
Sent: Thursday, June 01, 2006 5:36 PM
To: [email protected]
Subject: RE: [flexcoders] Re: Flex 1.5 Maintaining tree node state after
dataprovider refresh
If the trees are large, Karl might want to optimize his method for
efficiency.
One approach I have considered is this: on getting the tree data, build
an associative array that uses an id as a key and contains a reference
to the node. That way you would have random access to any node using
the id. You would take a performance hit up front building the
associative array, but thereafter retrieving a node would be much faster
from the hashed list than by recursing all nodes and comparing the id.
To record a tree's state when a node opens, you would start with the
just opened node and put it in the state array, and then climb up the
tree, one parent at a time. If any parent node exists in the state
array(use an associative array here too), remove it. This way, for any
path of open nodes, you will only have one recorded node, the last one
in the chain.
To restore a tree's state, you would do a for..in loop over the state
array, and for each recorded node id, find the actual node reference in
the random access array/map. Then climb the tree by parent, opening
nodes as you go.
I may try to do an example of this.
Tracy
-----Original Message-----
From: [email protected] [mailto:[EMAIL PROTECTED] On
Behalf Of moyosaned
Sent: Thursday, June 01, 2006 5:08 PM
To: [email protected]
Subject: [flexcoders] Re: Flex 1.5 Maintaining tree node state after
dataprovider refresh
public function recurseAndOpen(x:XML, tree:Object){
for(var each in x.childNodes){
if(x.childNodes[each].attributes.isOpen){
var t =
tree.getDisplayIndex(x.childNodes[each]);
tree.setIsOpen(tree.getNodeDisplayedAt(t), true, false, false);
}
if(x.childNodes[each] != undefined){
this.recurseAndOpen( x.childNodes[each], tree
);
}
}
}
Maybe you can use this....... store --> .attributes.isOpen every time a
node opens or closes... on refresh fill the tree with new data. and use
the old structure as a lookup tree to reopen the nodes...
--- In [email protected], "Karl Johnson" <[EMAIL PROTECTED]>
wrote:
>
> I have tried many different methods without much success. I need to be
> able to maintain, or at least give the appearance to the end user that
> I have maintained, the state of the tree after a refresh of the
> dataprovider (meaning I set the dataprovider an xml result of a
> webservice every x minutes).
>
> Has anyone successfully accomplished this? I tried popluating an array
> of the indexes of all displayed nodes, and then after refresh, looping
> through the state array and calling setIsOpen and passing in
> getTreeNodeAt(indexStoredInArray), etc... But that only works with the
> top level.
>
> Any suggestions? Any help is very much appreciated.
>
> Thanks,
> Karl
>
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