As far as I understand, now I can work with superclass view directly
from constructor of inherited class after super() call?
public class A extends Box {
function A() {
addChild(new TextInput()); // causes exception
}
}
public class B extends A {
function B() {
super();
addChild(new TextInput()); // works correctly
}
}
Is this behaviour is okay and could be used by developers?
Sergey.
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