RE: [flexcoders] Finding the x/y position of an object

Tue, 08 Aug 2006 13:12:22 -0700

Are your code snippets in the app file, where 'this' is a reference to the application? Or did you make an MXML component based on HBox and the code snippets are from it so that 'this' is the nested object? In neither case does it look like the right logic to me.

 

In an application script, I think you want to do

 

    var pt:Point = new Point(0, 0); // position of nestedObject in its own coordinates (i.e., nestedObject's coordinates)

    pt = nestedObject.localToGlobal(pt) // position of nestedObject in global coordinates

 

or (more complicated and not recommended)

 

    var pt:Point = new Point(nestedObject.x, nestedObject.y); // position of nestedObject in its parent's coordinates (i.e., nestedObject.parent's coordinates)

    pt = nestedObject.parent.localToGlobal(pt) // position of nestedObject in global coordinates

 

Note that localToGlobal() returns a new Point; it doesn't change the Point passed in.

 

- Gordon

 

From: [email protected] [mailto:[EMAIL PROTECTED] On Behalf Of Shannon Hicks
Sent: Tuesday, August 08, 2006 9:18 AM
To: [email protected]
Subject: [flexcoders] Finding the x/y position of an object

 

I have a nested object (an HBox) in my app, and I'm trying to figure out the global x/y position of it.

 

I've tried this:

 

           var pt:Point = new Point(this.x,this.y);
           this.localToGlobal(pt);

 

But it always returns 0/0. Even if I do this:

 

           var pt:Point = new Point(parent.x,parent.y);
           this.localToGlobal(pt);

It's returning an odd value, like 0/90.... the actual x/y position of the object is somewhere around 350/275

 

Any ideas?

 

Shan

 

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