Also, you can use index loops with XMLList, which will give you control over the order if that is important:
for (var i:int=0;i<xmData().length;i++) xmlCurNode = xmlData[i] Tracy ________________________________ From: flexcoders@yahoogroups.com [mailto:[EMAIL PROTECTED] On Behalf Of Alex Sent: Friday, January 12, 2007 12:44 AM To: flexcoders@yahoogroups.com Subject: [flexcoders] Yes it does! Thanks + Sorry My mistake: >> for each (var d:Object in data.a.b..c){ I assumed that .. had scope
