try the following program in flex 2(they come from flex help documentation,):
<?xml version="1.0"?> <mx:Application xmlns:mx="http://www.adobe.com/2006/mxml";> <mx:Script> <![CDATA[ import mx.controls.*; import mx.events.*; private var myMenu:Menu; // Initialize the Menu control, and specify it as the pop up object // of the PopUpButton control. private function initMenu():void { myMenu = new Menu(); var dp:Object = [{label: "New Folder"}, {label: "Sent Items"}, {label: "Inbox"}]; myMenu.dataProvider = dp; myMenu.addEventListener("itemClick", changeHandler); popB.popUp = myMenu; } // Define the event listener for the Menu control's change event. private function changeHandler(event:MenuEvent):void { var label:String = event.label; popTypeB.text=String("Moved to " + label); popB.label = "Put in: " + label; popB.close(); Alert.show('y'); } ]]> </mx:Script> <mx:VBox> <mx:Label text="Main button mimics the last selected menuItem." /> <mx:PopUpButton id="popB" label="Edit" width="135" creationComplete="initMenu();"/> <mx:Spacer height="50"/> <mx:TextInput id="popTypeB"/> </mx:VBox> </mx:Application> the problem is in the changeHandler menuEvent handler function,after items in popupButton was clicked,changeHandler event function always execute twice.so everytime i click just 1 time,i got 2 Alert of 'y'!! PS:there were some time that it did act normal,eg:u click the first item of popupButton,but after that the "twice" effect comes again... tks for ur time and any replyment will be greatly appreciated.
