Setting properties on the ClassFactory for each itemRenderer is cool, but does anybody know if there is a way to set style properties for the item renderer?
thanks, mark --- In [email protected], "Thind, Aman" <[EMAIL PROTECTED]> wrote: > > Thank you so much Flexing. I wasn't aware I could pass parameters to an > itemrenderer like that. Read a lot of documentations on renderers but > never stumbled against that. > > And Thank you so much Harald. That method of finding the column name > inside the renderer itself is very cool. I just pasted your code in my > application and poof. Thanks again for taking out the time. > > Cheers, > Aman > > ________________________________ > > From: [email protected] [mailto:[EMAIL PROTECTED] On > Behalf Of Harald Dehn > Sent: Thursday, May 24, 2007 3:47 PM > To: [email protected] > Subject: RE: [flexcoders] One Item Renderer Component for Multiple > Columns in a DataGrid - How to find name of column being rendered? > > > > You could although access the column information in the following way > inside your ItemRenderer > > var dg:DataGrid = (listData) ? DataGrid(listData.owner) : null; > > var column:DataGridColumn = (dg) ? > dg.columns[listData.columnIndex] as DataGridColumn : null; > > Harald > > From: [email protected] [mailto:[EMAIL PROTECTED] On > Behalf Of Flexing... > Sent: Donnerstag, 24. Mai 2007 08:03 > To: [email protected] > Subject: Re: [flexcoders] One Item Renderer Component for Multiple > Columns in a DataGrid - How to find name of column being rendered? > > As mentioned in my previous email, you can pass the column name as > property to the ItemRenderer > > i.e. > > 1. Create a public var columnName in your ItemRenderer > > 2. Pass the column name as property to the ItemRenderer while creating > it. > > Here's the code you need to write > > var colRendererFactory:ClassFactory = new ClassFactory > (com.lehman.smd.util.ValueRenderer);; > > colRendererFactory.properties = {columnName:"mycol2"}; > > column.itemRenderer = colRendererFactory; > > http://flex-apollo.blogspot.com/2007/05/single-itemrenderer-for-multiple > .html > <http://flex-apollo.blogspot.com/2007/05/single-itemrenderer-for-multipl > e.html> > > On May 24, 2007, at 11:22 AM, Thind, Aman wrote: > > > > > > Hi Flexing, > > Thanks for the reply! > > Yes I already set my itemrenderers in actionscript using: > > column.itemRenderer = new ClassFactory > (com.lehman.smd.util.ValueRenderer); > > for all my columns. > > My problem is inside the itemRenderer component, I do not know the name > of the column that invoked it, so do not know which column value to pick > and render > > Eg this is my renderer: > > ------------------------ > > <?xml version="1.0" encoding="utf-8"?> > <mx:Text xmlns:mx="http://www.adobe.com/2006/mxml > <http://www.adobe.com/2006/mxml> " text="{formatValue(data)}" > color="{signColor}"> > <mx:Script> > <![CDATA[ > > import mx.formatters.NumberFormatter; > > [Bindable] > public var signColor:int; > > public function formatValue(data:Object):String > { > var value:Number = Number(data.<Do Not Know Which Column Name To Use > As Many Columns Render Using This > ); > > if(value < 0) > { > signColor = 0xff0000; > } > else > { > signColor = 0x000000; > } > > return numFormat.format(value); > } > > ]]> > </mx:Script> > > <mx:NumberFormatter id="numFormat" rounding="nearest" > useThousandsSeparator="true"/> > </mx:Text> > > -------------------------- > > where data = > > <resultdetail> > > <col1> > > "1234.5" > > </col1> > > <col2> > > "-5342" > > </col2> > > </resultdetail> > > Many Thanks, > > Aman > > ________________________________ > > From: [email protected] [mailto:[EMAIL PROTECTED] On > Behalf Of Flexing... > Sent: Thursday, May 24, 2007 2:24 PM > To: [email protected] > Subject: Re: [flexcoders] One Item Renderer Component for Multiple > Columns in a DataGrid - How to find name of column being rendered? > > > > You need to use Action-Script to set the column renders: > > var colRendererFactory:ClassFactory = newClassFactory(columnRenderer); > > colRendererFactory.properties = {columnName:"mycol1"}; > > column1.itemRenderer = colRendererFactory > > var colRendererFactory2:ClassFactory = newClassFactory(columnRenderer); > > colRendererFactory2.properties = {columnName:"mycol2"}; > > column2.itemRenderer = colRendererFactory2; > > Hope this helps. > > On May 24, 2007, at 10:40 AM, Thind, Aman wrote: > > > > > > Hello, > > I have many columns in my DataGrid that have similar values and I need > to render them in a similar manner. > > So I wish to write just one itemRenderer component and set that as the > renderer of all these columns. > > So I believe each column will invoke my renderer when my grid shows up. > > However, the default data that is passed to the itemRenderer is just the > XML notation of one single row that is currently being renderered in the > grid. > > I do not have any information regarding which column actually invoked my > renderer so do not know which value to use. > > Eg all my columns have the same component registered as their > itemRenderer and this is what I get in the "data" variable: > > <resultdetail> > > <col1> > > "1234.5" > > </col1> > > <col2> > > "-5342" > > </col2> > > </resultdetail> > > Now in my renderer I want to format the number but I do not know which > column invoked it and so which value to pick. > > Is there anything passed to the renderer that tells the header of the > column which is being currently rendered by the custom itemrenderer? > > I do not want to write renderer_col1, renderer_col2 etc as the columns > and their dataprovider are dynamic. > > Many Thanks, > Aman > LB | Tokyo > > > > > > > > > > > > > > > > > > > > - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - > - - - - - - - - This message is intended only for the personal and > confidential use of the designated recipient(s) named above. 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