It is not necessary to have a request object: service.send(); is fine
in your handler, trace the xml: trace(xml.toXMLString()); Do you have what you expect? Then approach your desired data one step at a time, tracing the content as you go. trace(xml.msRun[0].toXMLString()); Aso, you have empty brackets on the scan node. A typo? Tracy ________________________________ From: [email protected] [mailto:[EMAIL PROTECTED] On Behalf Of Alan Gruskoff Sent: Wednesday, December 12, 2007 11:53 AM To: [email protected] Subject: [flexcoders] Re: complex xml parsing Some clues: While you imported the Fault event, you never used it. You will get either a fault or result, check for both: service.addEventListener("fault", httpFault); Also, you arent sending anything with "service.send();". Put the contents in the paren, ex: "service.send(xmlObject);". Last, get rid of the listeners when they have done heir job: this.removeEventListener("result", httpResult); this.removeEventListener("fault", httpResult); *** --- In [email protected] <mailto:flexcoders%40yahoogroups.com> , "y.mauron" <[EMAIL PROTECTED]> wrote: > > > Dear all, > > Here is a fragment of xml. When I try to parse it like that : > > > import mx.rpc.http.HTTPService; > import mx.rpc.events.FaultEvent; > import mx.rpc.events.ResultEvent; > > public function addMzXMLSpectrum(path:String):void{ > var service:HTTPService = new HTTPService(); > service.url = path; > service.resultFormat="e4x"; > service.addEventListener(ResultEvent.RESULT, resultHandler); > service.send(); > } > > public function resultHandler(event:ResultEvent):void{ > var xml:XML = event.result as XML; > Alert.show(xml.msRun[0].scan[]); > } > > but I never obtain any result :-( Does someone has an idea why ?
