I think the following might work. I use this in a DataGrid and it works. // this will give the index of the lest most item that is visible var topIndex: int = myList.horizontalScrollPosition;
// to get the number of visible items, you need to subtract the maxHorizontalScrollPosition from the dataprovider length var numItemsInWindow:int = ICollectionView(myList.dataProvider).length - myList.maxHorizontalScrollPosition; - venkat http://www.venkatj.com --- In [email protected], "geoff" <[EMAIL PROTECTED]> wrote: > > I posted most of this on the adobe forum but so far haven't received > any ideas, so hopefully someone here will know. I've created an AS3 > class that extends the HorizontalList. What I'm trying to achieve is > the ability to have 2 buttons on my application and 2 methods in my > extended class that allow the user to scrollleft or scrollright. In > working with this I've found that I need to override the > scrollHorizontally method in the HorizontalList class. I've also found > that the this.iterator.bookmark.getViewIndex() method gives me the left > most item index that is visible. What I can't figure out is how to get > the right most visible item index to determine whether or not to scroll > any further to the right. I've spent about 3 hours digging through > debug variables and livedoc pages to find something that would give me > that info, but so far have found nothing. Anyone have any ideas? > Thanks. >
