this should do it myXML..*.(@label=="G312(50)").toXMLString());
----- Original Message ---- From: ravi6mrgn <[EMAIL PROTECTED]> To: [email protected] Sent: Wednesday, January 23, 2008 11:57:46 PM Subject: [flexcoders] xml node search using xpath method Hi All, I am using Flex 3.0. I am just running an application which receives xml using HTTPService. ------------ --------- --------- ---- xml looks like <?xml version=1.0" encoding="utf- 8"?> <body> <node1 label="HO(55800) "> <node2 label="G1(550) "> <node3 label="G12(550) "/> </node2> <node2 label="G2(55) "> <node3 label="G21(30) "/> <node3 label="G23(25) "/> </node2> <node2 label="G3(1000) "> <node3 label="G31(450) "> <node4 label="G311( 400)"/> <node4 label="G312( 50)"/> </node3> <node3 label="G32(550) "/> </node2> </node1> </body> ------------ --------- --------- ------ I receive the xml through a result event and i stored it into a XML Object named newXML. if i want to get the node that is having label as G312(50) the code goes like this // newXML.node1. node2.node3. node4.(@label= ="G312(50) ") which will returns a xmllist right? yes. it is working perfectly. My question is how can i get the node which is having label as "G312(50)" without using the node1.node2. node3.node4 Note: i am having an string which is having node1, node2, node3, node4 newStr = "node1.node2. node3.node4" Is there any way, i can use newStr like newXML.newStr. (@label=="G312( 50)") I just tried for 8 hours but i didn't get any result any Idea, suggestions, comments? Regards. Ravi ____________________________________________________________________________________ Never miss a thing. Make Yahoo your home page. http://www.yahoo.com/r/hs
