Here is another possibility.
Climb up the ancestor chain, saving the current node's childIndex() at each point, maybe in a delimited string. You chould then "replay" that string, using .child(i) to retrace your path. Tracy ________________________________ From: [email protected] [mailto:[EMAIL PROTECTED] On Behalf Of Tracy Spratt Sent: Friday, February 01, 2008 3:21 PM To: [email protected] Subject: RE: [flexcoders] Re: How can I save XML path deep inside my XML data ? Yes, you will need to do something like this, save a reference. On problem is that you can't easily run-time parse a string representation of an e4x expression. Look in the archives, there are some techniques that let you do it, but they are not simple. Save a reference, that is probably the best way. Another possibility: Find your node, then assign a special id attribute, with a unique string id value. Then use e4x to locate the node using that string id. Tracy ________________________________ From: [email protected] [mailto:[EMAIL PROTECTED] On Behalf Of Jhonny Everson Sent: Thursday, January 31, 2008 9:48 PM To: [email protected] Subject: Re: [flexcoders] Re: How can I save XML path deep inside my XML data ? I guess you haven't explained very well yet. But let's present you some approach that MAY be what you are looking. That's saving the reference. var lastMatch:XML; for (...){ if( condition_matched){ lastMatch = (absolute path); // myXml.books[0].book.covers.cover[2].items[2].data123 for example break; } } then you can use lastMatch as a reference to that absolute path. On Jan 31, 2008 10:18 PM, helihobby <[EMAIL PROTECTED] <mailto:[EMAIL PROTECTED]> > wrote: I mean, I would like to be able to get the same exact location in the XML path every time I run my for loop and stop on some condition. For example some sort of function that returns: myXml.books[0].book.covers.cover[2].items[2].data123 if data123 is the value in my For Loop that I break on ( match on ) on the XML in question. Hope this helps, Sean. --- In [email protected] <mailto:flexcoders%40yahoogroups.com> , "Tracy Spratt" <[EMAIL PROTECTED]> wrote: > > What do you mean by "...save the absolute path..."? > > > > Save a reference? > > > > Save a string representation of the ancestor chain? > > > > What do you want to do? > > > > Tracy > > > > ________________________________ > > From: [email protected] <mailto:flexcoders%40yahoogroups.com> [mailto:[email protected] <mailto:flexcoders%40yahoogroups.com> ] On > Behalf Of helihobby > Sent: Thursday, January 31, 2008 6:42 PM > To: [email protected] <mailto:flexcoders%40yahoogroups.com> > Subject: [flexcoders] How can I save XML path deep inside my XML data ? > > > > Hello, > > I have a very large XML. > > I have a function which reads the XML and finds something that I am > looking for ( lets say data123 ) > > Once I find it I wish to save the absolute path to it ... > Is that possible ? > > For example: > > I wish to save: > > myXml.books[0].book.covers.cover[2].items[2].data123 > > However I can not build the above statement since the XML is dynamic. > I wish for the function to return the absolute path of the item after > I find it ... > > Thanks in advance, > > Sean. > -- Jhonny Everson
