Sorry Tracy, I was being stupid and looking at the wrong thing. That hint will do just what I need - Thank you.
John --- In [email protected], "Tracy Spratt" <[EMAIL PROTECTED]> wrote: > > Do it the other way around. Find the nodes you want displayed, then use > xml.parent() to climb up the ancestor chain, expanding nodes as you go. > I have a simple example on www.cflex.net <http://www.cflex.net/> . > > > > Tracy > > > > ________________________________ > > From: [email protected] [mailto:[EMAIL PROTECTED] On > Behalf Of j_lentzz > Sent: Tuesday, February 12, 2008 4:28 PM > To: [email protected] > Subject: [flexcoders] How to expand nodes down in trees > > > > Hi, > > I have an app where I need open up the nodes of a tree to display a > node chosen through a search text. For example, if I type 'flex' in > the search box, I need to display all the nodes that have 'flex' in > their label. This means that I need to open all the parent nodes down > to that node. I'm using flex 2, so I can't use any new Flex 3 > methods. I have a routine that will recursively open up the parent > nodes from a given node, but it needs to start at the top of the tree > to work, so if many items are found it gets very slow. I'd like to do > it in a single pass. I can identify the nodes I want to display by > searching through the XMLList from calling > XMLListCollection(this.dataProvider).descendants(); Is there a way to > use this structure to determine the trail of nodes to open without > having to start at the top of the tree and recurse for each item? > > Thanks, > > John >
