I've been playing with this for the past week or so, and the best
option I have found is like this:
var dateOffset:Number;
if (newDate.selectedDate.getTimezoneOffset() ==
originalDate.getTimezoneOffset()) {
dateOffset = ((newDate.selectedDate.getTime() - originalDate.getTime
()) / 86400000);
}
else if((newDate.selectedDate.getTime() - originalDate.getTime()) <
0) {
dateOffset = ((newDate.selectedDate.getTime() -
(originalDate.getTime() + 3600000)) / 86400000);
}
else {
dateOffset = (((dtApptDate.selectedDate.getTime() - 3600000) -
originalDate.getTime()) / 86400000);
}
I could also gone through the steps to find the day of year for both
dates and simply subtracted, but this seemed easier.
--- In [email protected], "Ryan Matsikas" <[EMAIL PROTECTED]>
wrote:
>
> Convert both dates to the same timezone, I suggest UTC since its
already
> there, then do the math.
>
> On Fri, Apr 25, 2008 at 5:03 AM, Tom Chiverton <[EMAIL PROTECTED]>
> wrote:
>
> > On Tuesday 22 Apr 2008, jmfillman wrote:
> > > I assume that I need to account for that 1 hour, the question
is, how?
> >
> > Math.round() or similar is a bit of a blunt instrument, depending
on what
> > you
> > want the result to be when the timezone offsets are (say) >12
hours.
> >
> > --
> > Tom Chiverton
> > Helping to augmentatively syndicate 24/7 services
> > on: http://thefalken.livejournal.com
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