Yeah Doug, thats easy...
To many commitProperties() calls for my, my head is templated.
Mike
On Wed, Jun 11, 2008 at 1:10 PM, Doug McCune <[EMAIL PROTECTED]> wrote:
> or just do:
>
>
> f ( disabledDates[a] == stayLength[i] ) {
> Alert.show("Date Overbooked!", "Sorry", Alert.OK);}
> break;
> }
>
> Doug
>
> On Wed, Jun 11, 2008 at 9:55 AM, Michael Schmalle <[EMAIL PROTECTED]>
> wrote:
>
>> Hi,
>>
>> This might help;
>>
>> var i:int = 0;
>> var overbooked:Boolean = false;
>>
>>
>> while ( startDate <= endDate ){
>>
>> for (var a:int = 0; a <= disabledDates.length; a++) {
>>
>> stayLength[i] = year.toString() + "," + month.toString() + "," +
>> startDate.toString();
>>
>> if ( disabledDates[a] == stayLength[i] ) {
>> overbooked = true;
>> }
>>
>> i++;
>> startDate++;
>>
>> }
>>
>> if (overbooked)
>> {
>> Alert.show("Date Overbooked!", "Sorry", Alert.OK);
>> }
>>
>> Mike
>>
>> On Wed, Jun 11, 2008 at 12:24 PM, tspyro2002 <[EMAIL PROTECTED]>
>> wrote:
>>
>>> Hi,
>>>
>>> I have a problem where I am processing dates and cross checking them
>>> across two Arrays. One array holds user selected dates, the other
>>> holds dates which are disabled.
>>>
>>> The loop I have at the minute checks them OK but outputs an Alert box
>>> for every date which is the same.
>>>
>>> How can I adjust the code so that only one alert box is displayed?
>>>
>>> CODE SEGMENT
>>>
>>> var i:int = 0;
>>>
>>> while ( startDate <= endDate ){
>>>
>>> for (var a:int = 0; a <= disabledDates.length; a++) {
>>>
>>> stayLength[i] = year.toString() + "," + month.toString() + "," +
>>> startDate.toString();
>>>
>>> if ( disabledDates[a] == stayLength[i] ) {
>>>
>>> Alert.show("Date Overbooked!", "Sorry", Alert.OK);}
>>>
>>> }
>>>
>>> i++;
>>> startDate++;
>>>
>>> }
>>>
>>>
>>
>>
>> --
>> Teoti Graphix, LLC
>> http://www.teotigraphix.com
>>
>> Teoti Graphix Blog
>> http://www.blog.teotigraphix.com
>>
>> You can find more by solving the problem then by 'asking the question'.
>>
>
>
>
--
Teoti Graphix, LLC
http://www.teotigraphix.com
Teoti Graphix Blog
http://www.blog.teotigraphix.com
You can find more by solving the problem then by 'asking the question'.
