you always could compare points using distance between them Point.distance(p1,p2)< tolerance
--- In [email protected], "fumeng5" <[EMAIL PROTECTED]> wrote: > > Hi, > > I'm trying to compare 3 points but because of double precision in AS3 > i'm running into some issues with trailing digits causing the numbers > to not be equal, i.e. 1.25 != 1.2499999999999 > > what i'd like to figure out how to do is introduce a tolerance of say > .001. then i'd compare the test point against the other two points > saying: is testPoint.x within the range of point1.x and point2.x and > is testPoint.y within the range of point1.y and point2.y. if so, > return true. > > i just can't figure it out. here's what i have so far: > > public static function isEndPoint(p:Point, Lp1:Point, Lp2:Point):Boolean { > var tolerance:int = .001; > var newLp1:Point = new Point(tolerance * Lp1.x,tolerance * > Lp1.y); > var newLp2:Point = new Point(tolerance * Lp2.x,tolerance * > Lp2.y); > return (p.equals(newLp1) || p.equals(newLp2)); > } > > I guess I'm seeing that the equals() method at the bottom of this code > is not really what i want. Plus, multiplying everything by .001 > doesn't solve the problem as i'll essentially be using the same > numbers i started with. > > Can someone perhaps point me in the right direction here, please? I'm > not sure where exactly to go from here. > > Thanks, > > fumeng. >
