grr ...
tomany things at once.
EDIT
var fadeEffect:TweenEffect = getStyle("fadeEffect");
IS
var fadeEffect:TweenEffect = getStyle("hideEffect");
Mike
On 4/30/07, Michael Schmalle <[EMAIL PROTECTED]> wrote:
Opps,
I missed your first sentence.
var fadeEffect:TweenEffect = getStyle("fadeEffect");
// you might have to cast it if it is not a Fade instance or do an is
check.
But, getStyle() is what you want.
Peace, Mike
On 4/30/07, Michael Schmalle <[EMAIL PROTECTED]> wrote:
>
> Hi,
>
> Really all mxml are actionscript classes.
>
> So in your extended component;
>
> - create
> private var tween:Fade;
>
> In createChildren() or something like it;
>
> tween = new Fade(this);
> tween.alphaTo = getStyle("fadeAlphaTo");
> tween.alphaFrom = getStyle("fadeAlphaFrom");
> // any other defaults or initializations
>
> Then in a handler or method, trigger it.
>
> private function fadeTrigger():void
> {
> tween.play();
> }
>
> Remember, you can also add update and end handlers to the tween
> instance. You could reset this instance, play it in reverse(). Just check
> out the ASDoc's on Fade.
>
> Peace, Mike
>
>
> On 4/30/07, Claudia Barnal < [EMAIL PROTECTED]> wrote:
> >
> > When instantiating a component through mxml I can easily add an
> > effect
> > to the hideEffect parameter, but what if I always want that effect to
> > occur in an extended component?
> >
> > What method would I have to extend?
> > Or what event would I have to listen to?
> >
> > If using the fade effect, also what would be the best way to implement
> > it?
> >
> > Thank you for any help,
> > Claudia
> >
> >
>
>
>
> --
> Teoti Graphix
> http://www.teotigraphix.com
>
> Blog - Flex2Components
> http://www.flex2components.com
>
> You can find more by solving the problem then by 'asking the question'.
--
Teoti Graphix
http://www.teotigraphix.com
Blog - Flex2Components
http://www.flex2components.com
You can find more by solving the problem then by 'asking the question'.
--
Teoti Graphix
http://www.teotigraphix.com
Blog - Flex2Components
http://www.flex2components.com
You can find more by solving the problem then by 'asking the question'.
