Jacco van Schaik writes: > What you are missing is the meaning of the phrase "reflected image". > It's *not* whatever you see in the mirror but the point in space where > two different rays of light, originating from a single point on the > object come back together again. It's the point where you can hold up a > piece of paper and see a sharp projection of the object. > > If the object is in the focal point, the reflected rays will be > parallel, so there is no point where they come together, hence the > singularity. > > If the object is further away than the focal point, the reflected rays > converge in front of the mirror, making an inverted image. If the object > is closer than the focal point the reflected rays will diverge, so there > is a virtual image *behind* the mirror, which is right side up. > > I'd draw you a picture, but in this case ASCII art is woefully > inadequate :-) > > Sorry for the highly unscientific explanation. HTH.
Ok, so "what I see" is not the same as the "reflected image", I can accept that. However, is there anyway to predict "what I see" if I know things like the original size of the object, the distance from the object to the mirror, the mirror radius/focal length, and the distance of my eye to the mirror? Essentially what I'm looking for as the end result is the distance and size of the "what I see". Thanks, Curt. -- Curtis Olson IVLab / HumanFIRST Program FlightGear Project Twin Cities [EMAIL PROTECTED] [EMAIL PROTECTED] Minnesota http://www.menet.umn.edu/~curt http://www.flightgear.org _______________________________________________ Flightgear-devel mailing list [EMAIL PROTECTED] http://mail.flightgear.org/mailman/listinfo/flightgear-devel
