>Spitfire Mk IIA 

Ah - surprising!

Here is an email Rick "Fuelcock" sent me a short while ago. I
hope it helps. Sorry for the poor formating.
------------------- snip ---------------------
Rather than send you the GBE code , I will direct you to the site
where I got 
it:

http://www.aeromech.usyd.edu.au/aero/propeller/prop1.html

Just click on program 1 at the bottom of the page.  Program 2 (right
below) 
is mathlab code for the implementation without the bells and whistles.

I have been playing around with program 1, and have obtained very
encouraging 
results.

I keyed in a "Spitfire" prop with radius 1.55 m and a blade area of
0.98m^3.  
The program only let's you design a simple blade with a straight,
symetrical 
taper.  Rather than complicate things, I just kept the cord constant
at .210 
the radius to give a total area of .327m^3 per blade.  Not knowing
anything for 
sure about the blade angle at a given radius, I just used the default
pitch 
of 0.5, where:

pitch = 2pi * r tan theta and  theta is the geometric angle of the
blade at 
r.  The model also lets you tilt the whole blade +/- any desired angle
setting. 
  Assuming the max speed of the Spitfire to be 154.7 m/s, I toyed with
angle 
setting until I obtained a max prop efficiency at angle setting 19.45,
J value 
of 2.09, which corresponds to a true airspeed of 154.7 m/sec for a
1.55 m 
radius prop, engine running at 3000 rpm and gear ratio 0.477.  The
model produced 
a theoretical efficiency of about 85%, with Cq = 0.071.

Next, I calculated the torque, using the formula Q=Cq * rho * n^2 *
D^4, 
where n is prop rotation in revolutions per second ( the code converts
this to 
radians) and D is prop diameter.
I assumed rho of 0.5 Kg/m^3, an altitude of about 15,000 feet. I than 
multiplied the torque by angular velocity in radians per second, to
get the power 
(watts) needed to counteract the torque of the prop.  This worked out
to 865 KW, 
which converts to 1159 HP.   This is about 10% hiigher than what the
Merlin 
could actually put out at the shaft, but it's pretty damn good.
Remember, the 
model is known to be about 5% to 10% too optimistic in predicting
performance, 
so if you take this into account, the prediction is nearly spot on!
------------------- snip ---------------------

>Regards
>
>Vivian

Bye bye,
Wolfram.


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