> -----Original Message-----
> From: [EMAIL PROTECTED] 
> [mailto:[EMAIL PROTECTED] On 
> Behalf Of Jon S. Berndt
> Sent: Friday, March 23, 2007 10:29 PM
> To: FlightGear developers discussions
> Subject: Re: [Flightgear-devel] Phidot not zero.. And bank 
> angle constant...
> 
> > Hi,
> >
> > I'm sorry but its sounding a little anomalous to me.
> >
> > >From the kinematic relationships;
> >
> > p = phidot - psidot sin(theta)
> >
> > q = thetadot cos(phi) + psidot cos(theta) sin(phi)
> >
> > r = psidot cos(theta) cos(phi) - thetadot sin(phi)
> >
> > now for a steady turn, theta can be approximated close to 
> zero and for 
> > the thetadot is also close to zero and negligible.  So we are left 
> > with roughly;
> >
> > p = phidot
> >
> > q = psidot sin(phi)
> >
> > r  = psidot cos(phi)
> >
> > If we p q and r were to be measured in the body axis, I guess they 
> > would be zero.  But in the inertial frame;
> >
> > p = phidot = 0     since its in a level turn the bank angle would
> > be constant
> >
> > q = psidot sin(phi) = non zero since phi has a value and in the 
> > inertial frame the heading is changing
> >
> > r =  psidot cos(phi) = non zero again
> >
> > Therefore q and r should have values and so should psidot, but 
> > thetadot and phidot should be zero or close to zero.
> >
> > Am I missing something?  Please do let me know.
> 
> Sorry. I confused myself. I may have been thinking of body 
> accelerations, not rates. Or something.
> 
> Your equations look good.
> 
> I ran a test script with the JSBSim c172. In a constant turn 
> I saw this at steady state:
> 
> P = ~0
> Q = ~3.5 deg/sec
> R = ~6 deg/sec
> 
> Pdot = ~0
> Qdot = ~0
> Rdot = ~0
> 
> phi   = ~30 deg
> theta =  ~4 deg
> psi   = from 200 deg to 20 deg
> 
> phidot   = ~0.0
> thetadot = ~0.0
> psidot   = ~6 deg/sec
> 
> I think this works out about right. So, at least JSBSim is 
> working correctly.
> 
> Jon
> 


Yeah, what he said.... ;-}

Bill 


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