> > I whant to do a simple thing, to show a window inside other window.
> > The function fltk::Window::show_inside(Window * parent)
> > should do it, but it does not show the window and application can
> > not leave fltk::run()
> > ...
> > outer->show();
> > inner->show_inside(outer);
> > return fltk::run();
> > Where is the problem? Is it in FLTK or in the code shown above?
>
> I'm not an FLTK2 user, so this is a stab in the dark, but your outer
> window isn't actually shown until the fltk::run() handles the event.
>
> Can you arrange for outer's draw() method to show the inner window?
> Maybe with a static variable so that it is only shown the first time?
>
> Can you arrange for a timer event that will show inner after outer's
> draw() method has been called? Then it would be handled in fltk::run().
>
> D.
>
Thank you for reply!
I tried the following code and the result is the same, it does not show the
inner window.
fltk::Window * inner;
fltk::Window * outer;
void callback(fltk::Widget * w, void * data)
{
inner->show_inside(outer);
cout<<"should show inner, but it does not"<<endl;
}
int main()
{
outer = new fltk::Window(500,500, "outer");
inner = new fltk::Window(200,200, "inner");
outer->begin();
fltk::Button *b = new fltk::Button(20,20,50,50, "button");
b->callback(callback);
outer->end();
outer->show();
return fltk::run();
}
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