Commentary below:
> void doexit(fltk::Widget *, void *) {
> exit(0);
> }
You would do better to walk the window list and hide them in turn, just calling
exit() is a bit rough - though it works fine of course.
> void test(void)
> {
> while(1) {
> i++;
> if( i%10 == 0 ) {
> win->show();
> sleep(2);
> win->hide;
> fprintf(stderr, "\nTesting.........%d\n", i);
> sleep(1);
> }
> }
> }
You can't call sleep from within the callback methods - that will halt the
event loop, stopping your program. You need to use timers; see
Fl::add_timeout(..) for reference.
> int main_menu(void)
> {
> aaa = new fltk::Group(0, 0, 240, 320, "startup");
> aaa->set_vertical();
> aaa->begin();
> {
> fltk::Button* o = new fltk::Button(60, 140, 100, 20, "Logout");
> o->buttoncolor((fltk::Color)0x8eabe000);
> o->highlight_color((fltk::Color)0x8797e000);
> o->callback(doexit);
> }
> test();
> }
What do you think this piece of code is doing?
Where do you end the aaa group?
Also, this function is spec'd to return an int, but it does not return
anything, so I'm surprised your compiler didn't complain.
This function, and therefore your test() function, are called before you have
shown any wondow. What do you expect that to achieve?
> int main (int argc, char **argv) {
>
> fltk::Window *w;
> {
> fltk::Window* o = new fltk::Window(5, 21, 250, 266, "Demo");
> w = o;
> o->set_vertical();
> o->box(fltk::BORDER_BOX);
> o->buttonbox(fltk::FLAT_BOX);
> o->labelfont(fltk::TIMES_BOLD);
> o->textfont(fltk::TIMES);
> o->labeltype(fltk::ENGRAVED_LABEL);
> o->color((fltk::Color)0xe0d0da00);
> o->selection_color((fltk::Color)0xff00);
> o->selection_textcolor((fltk::Color)56);
> o->buttoncolor((fltk::Color)0xe08b8100);
> o->shortcut(0xff1b);
> o->begin();
> {
> win = new fltk::Window(0, 0, 240, 320, "child window");
> win->hide();
> }
> main_menu(); //initial menu
> o->end();
> o->resizable(o);
> }
> w->show(argc, argv);
> return fltk::run();
> }
>
>
> What I am doing is when i%10 becomes I want to show a separate
> window, just for two seconds. So this block of code will do it.
No, it will not - you can't use sleep() in this function. Use a timer.
>
> i++;
> if( i%10 == 0 ) {
> win->show();
> sleep(2);
> win->hide;
> fprintf(stderr, "\nTesting.........%d\n", i);
> sleep(1);
>
> There I am just showing a separate window and giving 2secs delay the
> hiding it. But when I compile it throwing error "statement cannot resolve
> address of overloaded function" . What should I change????
Lots - there seem to be many things awry in this code; can you post something
that is clearer, so we can advise better?
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