On Fri, Jun 13, 2008 at 2:00 PM, Dan Amelang <[EMAIL PROTECTED]> wrote:
>
> No, "min" is correct. The intention is that every edge contributes at
> most 1. Using max instead would allow a contribution to exceed one
> (which would be incorrect).

Whoops! Although what I said about the min function is correct, I
wasn't careful about explaining how it fits in with the whole formula.

At this point in the formula, we aren't restricting individual edge
contributions. We have already summed up the contributions. What we
are restricting at this point is the total contribution of the closed
path to a given pixel. And that value cannot be greater that 1
(meaning entirely opaque).

Sorry for any confusion,

Dan

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