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http://issues.apache.org/bugzilla/show_bug.cgi?id=29459 Error in processing xml-file with xsl-stylesheet Summary: Error in processing xml-file with xsl-stylesheet Product: Fop Version: 0.20.5 Platform: PC OS/Version: Windows NT/2K Status: NEW Severity: Normal Priority: Other Component: general AssignedTo: [EMAIL PROTECTED] ReportedBy: [EMAIL PROTECTED] If I run fop with: fop.bat -xml daten.xml -xsl daten.xsl daten.pdf I got the error: [ERROR] org.apache.fop.apps.FOPException: A table cell must be child of fo:table-row, not fo:table-body I chekc th fo-output with xalan.bat and all looks fine. If I run fop with: fop.bat xalanout.fo daten.pdf it works. I assume the probleme is located in the following codesnip: <xsl:if test="position() mod 2"> <xsl:text disable-output-escaping="yes"><fo:table-row height="14cm" > </xsl:text> </xsl:if> <xsl:call-template name="RezeptCell"/> <xsl:if test="not(position() mod 2)"> <xsl:text disable-output-escaping="yes"></fo:table-row> </xsl:text> </xsl:if> <xsl:if test="position()=last() and position() mod 2"> <xsl:text disable-output-escaping="yes"></fo:table-row> </xsl:text> </xsl:if>
