The function you want is called IsIdenticalObj. It’s documented in the manual.
gap> eList:=[0,0,0,0];
[ 0, 0, 0, 0 ]
gap> eL2:=[];
[ ]
gap> Add(eL2, eList);
gap> Add(eL2, eList);
gap> eL3:=[ [ 0, 0, 0, 0 ], [ 0, 0, 0, 0 ] ];
[ [ 0, 0, 0, 0 ], [ 0, 0, 0, 0 ] ]
gap> IsIdenticalObj(eL2[1],eL2[2]);
true
gap> IsIdenticalObj(eL3[1],eL3[2]);
false
gap>
Steve
> On 8 Nov 2018, at 11:02, Mathieu Dutour <mathieu.dut...@gmail.com> wrote:
>
> I have a question about memory management in GAP.
>
> If we do
> eList:=[0,0,0,0];
> eL2:=[];
> Add(eL2, eList);
> Add(eL2, eList);
> The state of eL2 is then [ [ 0, 0, 0, 0 ], [ 0, 0, 0, 0 ] ]
> Now if we do eL2[1][1]:=1 then we have eL2 being
> [ [ 1, 0, 0, 0 ], [ 1, 0, 0, 0 ] ]
> because eL2 actually contains two pointers to eList.
>
> On the other hand, if we write eL3:=[ [ 0, 0, 0, 0 ], [ 0, 0, 0, 0 ] ];
> and do eL3[1][1]:=1 then we have eL3 being [ [ 1, 0, 0, 0 ], [ 0, 0, 0, 0 ]
> ].
>
> Therefore the GAP object behavior depend on the way they are
> constructed.
>
> If one is given a matrix, is there a way to identify which one are pointing
> to another object? Because right now if one does not know how the objects
> are built then I do not know how to do it.
>
> Mathieu
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