Hi Ahmet, You might have to make your problem a little clearer.
Do you just want factorisations of a permutation into two parts, p*q? Then, for any permutation p, p*(p^-1*(1,3,4)) = (1,3,4), so for any p you can calculate q=p^-1*(1,3,4). Chris -----Original Message----- From: Ahmet Arıkan <ari...@gazi.edu.tr> Sent: 23 April 2021 08:27 To: forum@gap-system.org Subject: [GAP Forum] All factorizations of a permutation Dear Forum, I am almost new in GAP Is it possible to find all factorizations by GAP of a permutation in arbitrary S_n for suitable n. For example (1,3,4)=(1,2,3,4)*(2,3). How about all factorizations of (1,3,4) in S_5. Thanks in advance, Ahmet Arikan _______________________________________________ Forum mailing list Forum@gap-system.org https://mail.gap-system.org/mailman/listinfo/forum _______________________________________________ Forum mailing list Forum@gap-system.org https://mail.gap-system.org/mailman/listinfo/forum
