Dear Dima and Forum.
I don't understand how your answer solves my problem, perhaps there is a 
misunderstanding:

What I want are the unitary matrices representing the elements of the group G 
for an irreducible representation V.For so, we should conjugate the non-unitary 
matrices (given by GAP) by the matrix R=S.P with S^{-2} the diagonalization D 
of the matrix X of the Hermitian positive definite formobtained by the 
averaging (or in some other way) and P the matrix of the change of basis (into 
the eigenvectors basis of X).  In this process, we need the find the square 
root of D, i.e.  the square root of positive cyclotomic numbers.
Is there an other process for doing that without having to compute square root 
of positive cyclotomic numbers?
Best regards,Sébastien


     Le Mardi 20 janvier 2015 14h29, Dima Pasechnik 
<dmitrii.pasech...@cs.ox.ac.uk> a écrit :
   

 On Tue, Jan 20, 2015 at 07:31:56AM +0000, Palcoux Sebastien wrote:
> Dear Alexander and Forum,
> If the cyclotomic number is the square of a cyclotomic number, is there an 
> easy way to find it?
> The number I need are the eigenvalues of the matrix of the unitarized inner 
> product of an irreducible representation of a finite group (see the comment 
> of Paul Garett here: http://math.stackexchange.com/q/1107941/84284). This 
> matrix is positive, I guess its eigenvalues are always cyclotomic (true for 
> the examples I've looked, but I don't know in general), and I hope they are 
> square of cyclotomic. Thanks to these square roots I can compute the unitary 
> matrices for the irreducible representation.

You don't need to take square roots. If H is the Hermitian positive definite 
form
you obtained by the averaging (or in some other way) then H=LDL*, for 
L a lower-triangular matrix with 1s on the main diagonal, and D is a diagonal 
matrix.
L and D can be computed without taking square roots (and so they will stay 
cyclotomic). 
Then conjugating by L gives you the unitary form.

HTH,
Dmitrii


> Remark: a function on GAP computing the unitary irreducible representations 
> seems very natural, so if there is not such a function, this should means 
> that there are problems for computing them in general with GAP, isn't it?
> Best regards,Sebastien Palcoux        
> 
>      Le Mardi 20 janvier 2015 3h13, Alexander Hulpke <hul...@fastmail.fm> a 
>écrit :
>    
> 
>  Dear Forum,
> 
> > On Jan 19, 2015, at 1/19/15 2:18, Palcoux Sebastien 
> > <sebastienpalc...@yahoo.fr> wrote:
> > 
> > Hi,
> > Is it possible to extend the function Sqrt on the cyclotomic numbers?
> 
> How would you represent this root? In general the square root of a cylotomic 
> is not cyclotomic again. (You could form a formal AlgebraicExtension, but 
> then you lose the irrational cyclotomics for operations.)
> 
> Regards,
> 
>   Alexander Hulpke


  
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