Hello. In my previous example we replaced content up to first comma. I did nothing else than copy this expression to cover content up to 5th comma
In regular expressions you can use original (find) string in replace - substitution. String you want to use must be enclosed by brackets. (.*?\,.*?\,.*?\,.*?\,.*?\,) This is the first part, followed by content of 6th column (.*?)\, Whan you replace, you use $n, where n means order number of search part. What I did is return whole first part as $1 without changes in replace, enclose content of the 6th column with "" and add comma: $1"$2", ----------------------------------------------------------- You can exchange parts in replace. E.g. you have german date format (dd.mm.yyyy): 12.3.2014 you can change it to US format (yyyy/mm/dd): search: (\d+)\.(\d+)\.(\d+) replace: $3/$2/$1 -- <http://forum.pspad.com/read.php?2,63956,63987> PSPad freeware editor http://www.pspad.com
