On 14 May 2006, at 18:16, ik wrote:
You get only a proper fpc when build with make. The x86_64 is defined
and passed by the makefile.
May I ask why does it do such things ?! Why doesn't it use the already
the existed $define statments ?
You have to specify for which target you want to build the compiler.
This is selected using a define which is unrelated to any defines for
the host platform of the current compiler.
Jonas
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