> Peter Vreman wrote:
>> oldval:=value
>> divval:=value div divider
>> modval:=oldval-divval
>
> I don't see how this is correct ? And why you need oldval, you don't
> modify value ?
>
> oldval=5
> divval=5 div 2=2
> modval=5-2=3

Mistake... it should have been:

modval=oldval-(divval*divider)

oldval=5
divval=5 div 2=2
modval=5-(2*2)=1




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