On 06 Apr 2007, at 21:36, Colin Western wrote:
Can I ask what determines the precision of floating point
calculations are done in? It seems that fpc treats (for example,
with J declared as integer)
1/sqrt(J+1.0) as single
but
1/sqrt(J+1) as double
In 2.1.2 and 2.2, both will be evaluated as single (except on 80x87,
because it is not possible to tell the 80x87 to perform a particular
calculation using only single/double precision).
which seems counter-intuitive. In FORTRAN I can force double
precision evaluation with sqrt(J+1.0D0) but there is no equivalent
idea of a double constant in Pascal.
The Pascal equivalent is sqrt(j+double(1.0)).
Jonas
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