Hi
I would like to use a simple assignment operator for arrays, with which all
elements of an array are assigned to the same value, similar to an extended
initialize, not to zero but to a value of choice. A simple example for an
integer array would be:
myArray := 5;
With arrays with defined bounds, it works, but i was not able to do it with a
dynamic array. My test case is this:
program arrayAssign;
type
TmyArray = array of integer;
var
myArray: TmyArray;
index: integer;
operator := (const number: integer) theResult: TmyArray;
var
i: integer;
begin
for i := low(theResult) to high(theResult) do
theResult[i] := number;
end;
begin
setlength(myArray, 10);
writeln ('myArray: ', low(myArray), ', ', high(myArray));
myArray := 5;
writeln ('myArray: ', low(myArray), ', ', high(myArray));
for index := low(myArray) to high(myArray) do
writeln (index, ': ', myArray[index]);
end.
The output is:
myArray: 0, 9
myArray: 0, -1
The problem is that in the declaration of the operator, the functions low and
high seem to return the values of the type TmyArray, i.e. 0 and -1 and not the
values of the variable of the assignment statement, i.e. myArray and the
assignment nullifies the previous setlength. Is there any way around this and
obtain the actual values of myArray?
Michael, aka MiSchi.
_______________________________________________
fpc-devel maillist - fpc-devel@lists.freepascal.org
http://lists.freepascal.org/cgi-bin/mailman/listinfo/fpc-devel
