> On Dec 11, 2019, at 4:16 PM, Michael Van Canneyt <mich...@freepascal.org>
> wrote:
>
> It does gain something: it tells you it is NOT a varargs, but an array of
> const, which is a different beast altogether.
But it's a syntax equivalent for "a variable amount of arguments", i.e.
varargs. ;) I guess others don't see it this way however.
Regards,
Ryan Joseph
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