>Number: 188495
>Category: misc
>Synopsis: /etc/rc.d/jail, ezjail and Linux jails don't work with FreeBSD
>10.0
>Confidential: no
>Severity: non-critical
>Priority: low
>Responsible: freebsd-bugs
>State: open
>Quarter:
>Keywords:
>Date-Required:
>Class: sw-bug
>Submitter-Id: current-users
>Arrival-Date: Sat Apr 12 07:40:00 UTC 2014
>Closed-Date:
>Last-Modified:
>Originator: Holger Freyther
>Release: 10.0
>Organization:
>Environment:
FreeBSD 10.0-RELEASE-p1 FreeBSD 10.0-RELEASE-p1 #14 5464d00(10-releng)-dirty:
Sat Apr 12 05:49:26 UTC 2014
>Description:
I am using ezjail and have a Linux/Debian/Squeeze jail. Starting with FreeBSD
the jail can not be started. In the ezjail config I specify:
export jail_osmocom_builder_debian_flags="-l -U root"
When executing ezjail the following command will be executed:
/usr/sbin/jail -l -u root -i -f /var/run/jail.osmocom_builder_debian.conf -c
osmocom_builder_debian
Passing -l (or -u root) and -f together will generate a non comprehensive error
message of the jail command:
usage: jail [-dhilqv] [-J jid_file] [-u username] [-U username]
-[cmr] param=value ... [command=command ...]
jail [-dqv] [-f file] -[cmr] [jail]
jail [-qv] [-f file] -[rR] ['*' | jail ...]
jail [-dhilqv] [-J jid_file] [-u username] [-U username]
[-n jailname] [-s securelevel]
path hostname [ip[,...]] command ...
When removing the flags the jail command fails in determing the uid/id of root
inside the jail. This is to be understood as the database used in FreeBSD does
not exist in linux.
The only way to get it started is to remove three lines generated by
/etc/rc.d/jail
echo " exec.clean;"
echo " exec.system_user = \"root\";"
echo " exec.jail_user = \"root\";"
Otherwise the command will fail with:
jail: osmocom_builder_debian: getpwnam: No such file or directory
jail: osmocom_builder_debian: sleep 2: failed
>How-To-Repeat:
Attempt to start a non FreeBSD jail.
>Fix:
>Release-Note:
>Audit-Trail:
>Unformatted:
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