https://bugs.freebsd.org/bugzilla/show_bug.cgi?id=269688
Bug ID: 269688
Summary: memalign() produces division by zero if size is 0
Product: Base System
Version: 13.1-RELEASE
Hardware: Any
OS: Any
Status: New
Severity: Affects Some People
Priority: ---
Component: bin
Assignee: [email protected]
Reporter: [email protected]
The implementation is to just call aligned_alloc():
return (aligned_alloc(align, roundup(size, align)));
where roundup is this macro
:#define roundup(x, y) ((((x)+((y)-1))/(y))*(y)) /* to any y */
If size is 0 that will be
(0 + align - 1) / 0 * 0
That gives me
(gdb) r
Starting program: /usr/home/paulf/scratch/valgrind/memcheck/tests/memalign2
Program received signal SIGFPE, Arithmetic exception.
Integer divide by zero.
0x00000008002f3415 in memalign (align=0, size=<optimized out>) at
/usr/src/lib/libc/gen/memalign.c:39
39 return (aligned_alloc(align, roundup(size, align)));
My source code is
91 p = memalign(0, 100); assert(NULL == p);
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