> > > #pragma weak foo = bar
> > 
> > What's the correct way to do this now?
> I dont know. :-(  There are hacks that can work around it, but I think this
> is unintentional breakage.  I tried changing this:
> #pragma weak foo = bar
> to
> __weak_reference(bar, foo);

void f () __attribute__ ((weak, alias ("__f")));
(But that may come to the same thing).

o       Mark Murray
O.\_    Warning: this .sig is umop ap!sdn

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