> > > #pragma weak foo = bar
> > What's the correct way to do this now?
> I dont know. :-( There are hacks that can work around it, but I think this
> is unintentional breakage. I tried changing this:
> #pragma weak foo = bar
> __weak_reference(bar, foo);
void f () __attribute__ ((weak, alias ("__f")));
(But that may come to the same thing).
o Mark Murray
O.\_ Warning: this .sig is umop ap!sdn
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