> Hello, > > I'm having a trouble programming a special login shell, and would like > to hear any opinions on this. > > I want this shell (which automatically becomes a session leader) to > release its ctty but remain unterminated (the ctty must be taken by its > child). However, there seems to be no easy way to do this; termios(4) > says one must call setsid() to release its ctty, but setsid(2) says the > call will fail if the caller is already a session leader. > > Would there be any other way for a session leader to release its ctty > without terminating itself? TIA.
You need to also drop your process id so that you're not the owner of the process group that the terminal points at. Check bundle_setsid() in src/usr.sbin/ppp/bundle.c. A second fork() is done here because the parent may continue and doesn't want to figure out how to reap the child - you probably don't need this if the original process is going to go away soon anyway. > Cheers, > Eugene Kim > > PS. I'm now using a workaround that the shell will forward the SIGHUP > that it received because it's a session leader, but this isn't a clean > way. :-p > > -- > Eugene M. Kim NTT Multimedia Communications Laboratories > Software Developer 250 Cambridge Avenue, Suite 205 > +1 650 833 3630 (Voice) Palo Alto, CA 94040, USA > +1 650 833 3633 (Fax) mailto:g...@nttmcl.com -- Brian <br...@awfulhak.org> <br...@freebsd.org> <http://www.Awfulhak.org> <br...@openbsd.org> Don't _EVER_ lose your sense of humour ! <br...@uk.freebsd.org> To Unsubscribe: send mail to majord...@freebsd.org with "unsubscribe freebsd-hackers" in the body of the message
