In message <[EMAIL PROTECTED]>, [EMAIL PROTECTED] writes:
>In message <[EMAIL PROTECTED]> Marc Tar
>dif writes:
>: So why is %esp displaced by 16 bytes when only 8 bytes
>: are necessary (4 for $0 and 4 for $.LC0)? And couldn't
>: the compiler use a single instruction such as
>: subl $16,%esp or addl $-16,%esp? Are two instructions
>: used for pipelining purposes, where subl is synchro-
>: nised with the first pushl and addl with the second
>: pushl?
>
>gcc tries to align stack to 16 byte boundaries as a speed
>optiminzation. Why it doesn't do this in one instruction is beyond
>me.
Kocking 16 bytes off the stack pointer won't put it any closer to a
16 byte boundary.
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