Hi folks,
Is there a good reason why sysctl(8) won't display _any_ output for
opaque MIB entries named as arguments? I'm specifically interested in
kern.proc.all. I can ``sysctl -A | grep kern.proc.all'', but it's weird
that neither of these two do anything useful:
sysctl -A kern.proc.all
sysctl kern.proc.all
Is there some sound reason for this, or am I just lost on the fringes of
what sysctl(8) was designed for?
Ciao,
Sheldon.
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- Re: sysctl(8) and opaque MIB entries Sheldon Hearn
- Re: sysctl(8) and opaque MIB entries Dag-Erling Smorgrav
- Re: sysctl(8) and opaque MIB entries Sheldon Hearn
- Re: sysctl(8) and opaque MIB entries Dag-Erling Smorgrav
- Re: sysctl(8) and opaque MIB entries Peter Pentchev
- Re: sysctl(8) and opaque MIB ent... Dag-Erling Smorgrav
- Re: sysctl(8) and opaque MIB... Peter Pentchev
- Re: sysctl(8) and opaque... Dag-Erling Smorgrav
- Re: sysctl(8) and opaque MIB entries Poul-Henning Kamp
- Re: sysctl(8) and opaque MIB entries Peter Pentchev
- Re: sysctl(8) and opaque MIB entries Dag-Erling Smorgrav

