In a message written on Sun, Jul 20, 2003 at 02:13:52PM -0700, Tim Kientzle wrote: > If I declare argv as "const char *", > then the call to execve() warns about > "incompatible pointer type" for the > second argument.
Almost, but the other order is important here, this passes gcc -Wall:
#include <unistd.h>
#include <paths.h>
int main(int argc, char *const argv[], char *const envp[]) {
char *const execargv[] = { _PATH_BSHELL, NULL };
execve(_PATH_BSHELL,execargv,envp);
return 0;
}
--
Leo Bicknell - [EMAIL PROTECTED] - CCIE 3440
PGP keys at http://www.ufp.org/~bicknell/
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