[EMAIL PROTECTED] wrote:
> On Wed, Mar 02, 2005 at 04:33:16PM -0800, ALeine wrote:
> > [EMAIL PROTECTED] wrote:
> > > It is _plainly_obvious_ that if you encrypt 2^30 sectors each
> > > with a different 128 bit key then there are at most 2^158
> > > different
> > > ways to decrypt the entire disk. Period.
> >
> > out which of the 2^128^(2^30) sector variations is the right
> one?
>
> Which, I think, is 2^(128 + 30) == 2^158, which is what Roland
> said.
No, you are wrong.
2^128*2^30 = 2^158
We are actually dealing with:
(2^128)^(2^30) = 2^(128*2^30) = 2^(2^37) = 2^137438953472
^--- notice the minor difference
ALeine
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