Hello list
I have an application that simply logs in as another user
and runs "screen -x". The problem I am having with the
followin code is that the results of execution is a message
from (I am guessing the shell) saying that I dont have access
to the "/dev/ttyp?" where ? is the current virtual terminal
that I am running on.
Here is my application:
#include <stdlib.h>
int main(int argc, char* pszArgs[])
{
int result;
result= system("/usr/bin/su ppp -m --login -c " &
"/usr/local/bin/screen -x");
return result;
}
And here is the output:
bash-2.05$ ./a.out
To see the output from when your computer started, run dmesg(8). If it has
been replaced with other messages, look at /var/run/dmesg.boot.
-- Francisco Reyes <[EMAIL PROTECTED]>
Cannot open your terminal '/dev/ttyp0' - please check.
Thank you all for your time.
Aaron Burke
[EMAIL PROTECTED]
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