On 11/2/06, Steve Bertrand <[EMAIL PROTECTED]> wrote:
mybox# ifconfig rl0: flags=8843<UP,BROADCAST,RUNNING,SIMPLEX,MULTICAST> mtu 1500 options=8<VLAN_MTU> inet 126.96.36.199 netmask 0xffffff80 broadcast 188.8.131.52 inet 192.168.250.1 netmask 0xffffff00 broadcast 192.168.250.255 ...now, mybox# ifconfig rl0 delete 192.168.250.1 ...and finally, newmarlo# ifconfig rl0: flags=8843<UP,BROADCAST,RUNNING,SIMPLEX,MULTICAST> mtu 1500 options=8<VLAN_MTU> inet 184.108.40.206 netmask 0xffffff80 broadcast 220.127.116.11
This seems to work for IPv4 address as I tried the above. I added the address and then deleted it. However, when I attempt to delete the IPv6 address I've given to the interface, I continually get "bad value." For example, ifconfig sis0 inet6 fec0:1:1:1::2/64 ifconfig sis0 delete fec0:1:1:1::2 Which returns: ifconfig: fec0:1:1:1::2: Bad value I've even tried expressing all 8 "blocks" of the IPv6 address. Could this be a defect in how ifconfig handles IPv6 addresses? If so, whom do I contact to look into it? Andy _______________________________________________ firstname.lastname@example.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to "[EMAIL PROTECTED]"