On 11/28/06, Jerry McAllister <[EMAIL PROTECTED]> wrote:
On Mon, Nov 27, 2006 at 09:24:30PM -0500, David Banning wrote:

> I am attempting to setup a secondary ide drive. I have configured the
> entire 305MB drive for storage. I used /stand/sysinstall and -it-
> issued the command ;
> /bin/sh -c newfs -b 16384 -f 2048 /dev/ad2s1e
> which seems very disk intensive and is taking a long time. I am wondering
> if this is right. I just want to use the second drive as a storage folder
> for backing up the main drive.
> The disklabel editor shows it as
> Disk: ad2       Partition name: ad2s1   Free: 0 blocks (0MB)
> Part      Mount          Size Newfs   Part      Mount          Size Newfs
> ----      -----          ---- -----   ----      -----          ---- -----
> ad2s1e    /uusr       305242MBUFS+S Y
> This configuration issued the command as above;
> /bin/sh -c newfs -b 16384 -f 2048 /dev/ad2s1e
> How long should newfs take for a 305 MB drive?

Do you really mean 305 GB drive?
It depends some on your CPU and the speed of the drive.
My guess would be in the range of 15 minutes or so.
It has to write all the alternate superblocks.   I haven't
studied it, but I have always wondered if it is necessary to
have so many alternate superblocks.

You can, of course, bsdlabel* and newfs without touching

I have not played with it tons, but I suspect that the number
of alternate superblocks is dependant on the -b flag to
newfs.  I remember running into a (or what seemed a) rather
conservative maximum for this value, 65536, I seem to recall.

If you are primarily going to be writing very large files, like
tar files, there should be no harm in having a very large block
size and sparse inodes, though changing it might require
a wipe and a newfs, should you decide to make the disk your
databse storage for a couple million 1k files.

*I am just now reading man gpt, and let me tell you, I am both
frightened and a bit confused.

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