This is an awk-type question.  Hopefully a one-liner.  If I
        need to use #!/usr/bin/awk and a BEGIN/END (or whatever it is),
        that's okay...

        I want to do an ls -l in a  /home/kline/<directory> and find and
        edit files that are dated (let's say) Apr 19 or Mar 26.  This
        works to print $9 the filenames.  

         ls -l| awk '{if ($6 == "Apr" && $7 == 19  || $6 == "Mar" && $7
         == 26 ) print $9}'

         What's the final part to get awk to vi $9?  Or another pipe and
         xargs and <what> "vi"?  Nothing simple works, so thanks for any



  Gary Kline  [EMAIL PROTECTED]  Public Service Unix

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