I get an error;
sed: illegal option -- d
usage: sed script [-Ealn] [-i extension] [file ...]
sed [-Ealn] [-i extension] [-e script] ... [-f script_file] ... [file
...]
here's my script
for i in $(cat /usr/path/test1);
do
sed -e s#old1#new1\ cut -d, -f 1 ${i}# -e s#old2#cut -d, -f 3 ${i}# file1
> file2
done
cat test1
boby, e, 656a,
allen, e, 987c,
...
----- Original Message -----
From: "Tino Engel" <[EMAIL PROTECTED]>
To: "Halid Faith" <[EMAIL PROTECTED]>
Cc: <freebsd-questions@freebsd.org>
Sent: Tuesday, December 11, 2007 11:22 PM
Subject: Re: How to replace two strings in a file in the same time with sed
command ?
> Halid Faith schrieb:
> > Ok
> > But I have another problem,
> > I couldn't use any command interior of sed command. That's to say I
have a
> > script;
> >
> > yy="file5"
> > for i in `cat file1`;
> > do
> > sed -e 's/old1/new1\ \'$i'/g' -e 's/old2/'cut -d, -f 1 ${yy}'/g'
file2 >
> > file3
> > done
> >
> > When I run the script, I get an error, due to using cut command
> >
> >
> >
> >
> For using environment variables in sed, you have to use # instead of /
>
> VAR="TEXT"
>
> sed s#OLD#${VAR}#g file1
>
> Will replace OLD by TEXT. Do not use quotations here...
> Rg, Tino
> _______________________________________________
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